std:: remove_reference

If the type T is a reference type, provides the member typedef type which is the type referred to by T . Otherwise type is T .

If the program adds specializations for std::remove_reference , the behavior is undefined.

Contents

[edit] Member types

[edit] Helper types

template < class T >
using remove_reference_t = typename remove_reference < T >:: type ;

[edit] Possible implementation

templateclass T> struct remove_reference { typedef T type; }; templateclass T> struct remove_referenceT&> { typedef T type; }; templateclass T> struct remove_referenceT&&> { typedef T type; };

[edit] Example

Run this code

#include #include int main() { std::cout  std::boolalpha; std::cout  "std::remove_reference::type is int? "  std::is_sameint, std::remove_referenceint>::type>::value  '\n'; std::cout  "std::remove_reference::type is int? "  std::is_sameint, std::remove_referenceint&>::type>::value  '\n'; std::cout  "std::remove_reference::type is int? "  std::is_sameint, std::remove_referenceint&&>::type>::value  '\n'; std::cout  "std::remove_reference::type is const int? "  std::is_sameconst int, std::remove_referenceconst int&>::type>::value  '\n'; }

std::remove_reference::type is int? true std::remove_reference::type is int? true std::remove_reference::type is int? true std::remove_reference::type is const int? true